$$ M_{max} = \frac{wL^2}{8} = \frac{2 \times (20)^2}{8} = 100 \text{ kip-ft} $$ (Convert to kip-in: 100 * 12 = 1,200 kip-in) simplified design of steel structures pdf
In the world of construction and civil engineering, steel is king. Its high strength-to-weight ratio, ductility, and recyclability make it the backbone of skyscrapers, industrial sheds, bridges, and residential frames. However, for students, junior engineers, and even seasoned professionals switching from concrete to steel, the path to mastering structural design often feels blocked by a wall of complex codes (like AISC, Eurocode 3, or IS 800) and intimidating differential equations. $$ M_{max} = \frac{wL^2}{8} = \frac{2 \times (20)^2}{8}
You need to select a W-shape steel beam (A992 steel, Fy=50 ksi) to span 20 feet, supporting a uniform load of 2 kips/ft (including self-weight). Deflection is limited to L/360. You need to select a W-shape steel beam
